line of code with space$(). This one works wrong, not givin

[jarych]

...not giving any spaces, and I know these should have some.


This whole sample program which fails to give the spaces according to the line of code:

'use between the columns, of 13 13 13

nm1$="conical"
nm2$="rectangular"
nm3$="square"
nm4$="cylinder"


print i;space$(6);nm1$;space$(len(nm1$)-13);nm2$;space$(len(nm2$)-13);nm3$;space$(len(nm3$)-13);nm4$


END

I cannot understand what is wrong that only the first two variables are given the spaceing but the others are smashed together.

[jarych]

Maybe I found something to help in straightening my own problem in this example try.

Including two different "print" code lines, one of the seems much better than the other:


'use columns of 13 13 13

nm1$="conical"
nm2$="rectangular"
nm3$="square"
nm4$="cylinder"


print space$(6);nm1$;space$(len(nm1$)-13);nm2$;space$(len(nm2$)-13);nm3$;space$(len(nm3$)-13);nm4$
print space$(6);nm1$;space$(13-len(nm1$));nm2$;space$(13-len(nm2$));nm3$;space$(13-len(nm3$));nm4$


END

[Rod]

Since the word conical is seven characters long and you deduct thirteen from it you get minus six spaces! Reverse the maths.

[jarych]

I figured out the remedy. I believe what I did is same as what you just told me. I see you found what I might do while I was doing it. (Fixed the problem in a different program too.)