using() question

[casco]

Why does a percent sign appear in the negative result?
pos=sqr(2)
neg=-1*sqr(2)
print "pos = ";using ("#.####", pos)
print "neg = ";using ("#.####", neg)
end


[Rod]

It is telling you that you are overflowing the space you allowed. The - is being treated as a digit and -1 is more than # it would need ##

Its a presentation tool, so if it matters you might add the sign separately and use the abs() value for the #.####

[tsh73]

Just use "##.####" so you allocate place for minus sign as well.

[casco]

Aha. So in anticipation of negative values, one more # is needed in the integer part. Thanks.