Dealing with odd numbers and rounding down

[Horizon]

Hello,

Here is a quick question. Whats the best way to detect an odd number?
As i'd like to sort odd numbers from even ones (with a rounding down function).

The process I'm looking to achieve is this:
If my number is odd then round down to the next lower even number (-1 easy enough).

For example:
input = 9 output = 8
input = 6 output = 6
input = 5 output = 4
input = 79 output = 39 etc. etc.

Would using INT to determine if I divide the input number by two that there is a decimal (3 becomes 1.5), but perhaps this is overkill?

Any pointers would be most welcome.

[B+]

Hello Horizon, I use MOD 2. If number MOD 2 = 0 then PRINT number;" is even." else PRINT number;" is odd."

n MOD m is like dividing a number by m and only looking at the remainder.

7/2 has remainder = 1

8/2 has remainder = 0 because 2 divides 8 perfectly, no Remainder.

INT(number/2) would drop the stuff after decimal so another way

IF number/2 = INT(number/2) then Print "Number is even.")

[Horizon]

Hello B+

That's perfect, thanks so much for the example.

[B+]

We cross posted, I added a thing about INT.

[tsh73]

rounding to even
for i = -5 to 10
   print "input", i, "output", int(i/2)*2, i - i mod 2
next



[B+]

Ha! cool tsh73, I always liked 5's and 13's

for i = -5 to 100
   print "input", i, "output", int(i/5)*5, int(i/13)*13
next


[ntech]

How about this?


function evenNumber(n)

 ''
  ' evenNumber() accepts a number and returns it if it's even
  ' or else it returns the even number immediately before it.
 ''

 if n/2=int(n/2) then
   evenNumber = n
 else
   evenNumber = n-1
 end if

end function


[zzz000abc]

here is one more
for i=-5 to 10
print "input ";i,"output ";i-(abs(i) mod 2 =1)
next